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CosA/1-tanA+sinA/1-cotA=sinA+cosA

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CosA/1-tanA+sinA/1-cotA=sinA+cosA

Posted by Manoj Singh 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Yaar 6 years, 11 months ago

LHS =cosA/(1-tanA)+sinA/(1-cotA) =cos A/(1 - sin A/cos A) + sin A/(1 - cos A/sin A) =cos²A/ (cos A - sin A) + sin²A / (sin A - cos A) =cos²A/ (cos A - sin A) - sin²A / (cos A - sin A) =(cos ² A - sin ² A) / (cos A - sin A) =(cos A - sin A)(cos A + sin A) / (cos A - sin A) =cos A + sin A i.e RHS Read more on Brainly.in - https://brainly.in/question/1346932#readmore

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