Find the value of k for …

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Ram Kushwah 6 years, 11 months ago
x2+k(4x+k-1)+2=0
X2+4kx+k2-k+2=0
If roots are equal then
b2=4ac
Here a=1,b=4k c=k2-k+2
So (4k)^2=4×1×(k^2-k+2)
4k^2=k^2-k+2
3k^2+k-2=0
3k^2+3k-2k-2=0
3k(k+1)-2(k+1)=0
(3k-2)(k+1)=0
k=2/3, .- 1
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