LHS: Sin-cos+1/sin+cos-1. = ((sin-cos+1)/cos)/(sin+cos-1)/cos =Tan+sec-1/tan-sec+1 === substitute sec^2-tan^2 in place of +1 =Tan+sec-1/tan -sec+(sec^2-tan^2) =Tan+sec-1/tan-sec+(sec-tan)(sec+tan) =Tan+sec-1/-(tan-sec)(sec+tan-1) =1/sec-tan

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Vishal Aryan 6 years, 11 months ago

Explain the every thing

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Sahitha?? Sharma 6 years, 11 months ago

Can't understand the question.?

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Prince Garg 6 years, 11 months ago

Sin -cos+1÷sin +cos -1 = 1÷sec-tan

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