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7sin^2A+3cos^2A=4.S.T: tanA=1/√3

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7sin^2A+3cos^2A=4.S.T: tanA=1/√3
  • 1 answers

D.J Alok 6 years, 11 months ago

4sinAsq+3sinAsq+3cosAsq=4 3(sinAsq +cosAsq)+4sinAsq=4 3+4sinAsq=4 4sinAsq=1 SinAsq=1/4 SinA=√1/4=1/2 SinA=30 TanA=30 TanA=1/√3
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