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If the equation(1+m2)x2+2mcx+(c2-a2)=0 has equal roots …

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If the equation(1+m2)x2+2mcx+(c2-a2)=0 has equal roots ,prove that c2=a2(1+m2)
  • 2 answers

Ashish Garhwal 6 years, 5 months ago

Given- (1+m2)x2+2mcx+(c2-a2)=0 If this equation has equal roots then B2-4ac = 0 (2mc)2-4(1+m2)(c2-a2)=0 4m2c2-4(1+m2)(c2-a2)=0 4m2c2 = 4(1+m2)(c2-a2) m2c2 = (1+m2)(c2-a2) m2c2 = c2 - a2 + m2c2 - m2a2 0 = c2 -a2 - m2a2 m2a2 = c2-a2 m2a2 + a2 = c2 (1+m2)a2 = c2 HENCE PROVED ????

Kuldeep Singh 6 years, 5 months ago

Not knowing
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