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Find the sum of the following …

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Find the sum of the following series up to n terms: (1) 5+55+555+... (2) .6+.66+.666+... Please solve this question in simple

    • Posted by Narendra Sahu 6 years, 11 months ago

    CBSE > Class 11 > Mathematics
    • 3 answers

    Ankit Singh 6 years, 11 months ago

    Great answer

    1Thank You

    Yakshi ? 6 years, 11 months ago

    Wait wait wait......i did not tell u something.....that is.......let (-1-1-1-1.....)=n and as u know sum of infinity.......as 10+10^2+10^3.......= [{10^(n+1) - 10} /9] -n........so.......ur answer will be......5/9[ {10^(n+1) - 10 -9n}/9]

    2Thank You

    Yakshi ? 6 years, 11 months ago

    In first part......1) 5+55+555........u can take 5 as common then it will be = 5( 1+11+111....) = now....multiply and divide it by 9.....then u will get....(5/9){9+99+999.......} .....u can write 9 as (10-1) and 99 as (100-1) and so on......so .....it will be......(5/9){ 10-1 + 100-1 + 1000 -1............}......in this case there will be two parts...... in first one u will find sum of all the " 1" in this....and in second one u will write 100 as 10^2 ......1000 as 10^3...and so on then find sum of (10+10^2+10^3.......).......then u will get......

    3Thank You

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