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Find the value of k for …

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Find the value of k for which x²+(k-1)x+k²-16 is exactly divisible by (x-3) but not divisible by x+4
  • 2 answers

Akshit Bihal 6 years, 11 months ago

Hahaha

Ram Kushwah 6 years, 11 months ago

For X=3

3^2+(k+1)x3+k2-16=0

K​​​​​​2+3k-4=0

(K+4)(k-1)=0 k=-4,1

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