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√(-a cos alpha-a sin alpha)^2 + …

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√(-a cos alpha-a sin alpha)^2 + (b sin alpha-(-b cos alpha))^2
  • 2 answers

Yaar 6 years, 11 months ago

Or, a^2 + b^2 + 2SinaCosa( a^2 - b^2) But both are same

Yaar 6 years, 11 months ago

(a^2 + b^) 1 - 4sin^2a cos^2a Where a is alpha
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