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Why the range of f(x)=√(9-x^2) is …

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Why the range of f(x)=√(9-x^2) is [0,3] ? It should be [-3,3] because answer of root will be positive and negative both. help if u know
  • 1 answers

Aditya Sharma 6 years, 11 months ago

√9–x² Domain: 9–x² > 0 (3+x)(3–x)>0 Domain belongs to [–3,+3] RANGE: –3<x<+3 [0,3]
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