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If the hcf of 210 and 55 is expressible in the form 210*5+55y then find y

Posted by Dinesh Hadapad 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Raunak Pandey ?? 6 years, 11 months ago

Applying Euclid division lemna on 210 and 55, we get 210 = 55 × 3 + 45☺️☺️ 55 = 45 × 1 + 10 ☺️ 45 = 4 × 10 + 5 ☺️ 10 = 5 × 2 + 0 ☺️ ☺️We observe that the remainder at this stage is zero. So, the last divisor i.e., 5 is the HCF of 210 and 55.☺️ ∴ 5 = 210 × 5 + 55y☺️ ⇒ 55y = 5 - 1050 = -1045☺️ ☺️∴ y = -19

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