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Find the value of `k` so …

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Find the value of `k` so that the following quadratic equestion has equal roots.... 2x2-(k-2)x+1=0

Posted by Mukesh Baro 6 years, 11 months ago

CBSE > Class 10 > Mathematics

5 answers

Saniya Sarfaraz 6 years, 11 months ago

b2-4ac=0 -(k-2)^2-4×2×1 (-K+2)^2-8 K^2+4-4k-8 K^2-4k-4=0 K^2-(2+2)k-4=0 K^2-2k-2k-4=0 K(k-2)-2(k-2) (K-2)(k-2) K=2,k=2 Hence the value of k is 2

Mukesh Baro 6 years, 11 months ago

Anushka...i use it bt the eq. i get was.. k square - 4k-4=0

Mukesh Baro 6 years, 11 months ago

The equation is. 2x2-(k-2)x+1=0

Anushka Jugran ? 6 years, 11 months ago

U can use the formula" b square - 4ac=0"

Saniya Sarfaraz 6 years, 11 months ago

Can you write the equation once again

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