Find the sum of those integers …

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Posted by Mohit Macpherson 6 years, 11 months ago
- 3 answers
Ram Kushwah 6 years, 11 months ago
Multiples of 2 are
2,4,6....500
S2 =250/2×(2+500)=125×251=31375
Multiples of not included are
5,15,25,35......495
If n are the numbers then
495=5+(n-2)×10
490+20=5n, n=510/2=255
S5 =255/2×(5+595)=600×255/5=76500
Total sum =32375+76500=108875
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Ram Kushwah 6 years, 11 months ago
Sorry there was mistaken
Sum even numbers from 1to 500 are
S2=1/4×500×502=62750......(1)
The multiples of 5 not included are
5,15,25,.....495
If n are terms then 495=5+(n-1)×10
490=10n-10. n=50
So S5=50/2×(5+495)=25×500=12500
Total sum S2+S5=
=62750+12500=75250
0Thank You