Find three numbers in A.P. whose …
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Posted by Armandeep Dhillon 6 years, 11 months ago
- 4 answers
Gaurav Seth 6 years, 11 months ago
a-d,a,a+d
a-d+a+a+d=21
3a=21
a=7
product=a-d*a*a+=315
multiply them u will get value of d=2
subsitute the value in a-d,a,a+d
numbers are 5,7,9
Gaurav Seth 6 years, 11 months ago
Let the number be (a-d), a, (a+d)
(a-d)+a+(a+d)=21
a-d+a+a+d=21
3a=21
a=7
(a-d)×a×(a+d)=231
(a²-d²)×7=231
a²-d²=33
7²-d²=33
49-d²=33
d²=49-33
d²=16
d=4
Numbers = 3,7,11
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Ankit Singh 6 years, 11 months ago
1Thank You