An aeroplane leaves an airport and …
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Sia ? 6 years, 6 months ago
Distance traveled by the plane flying toward north in {tex}1\frac{1}{2}{/tex}hrs
{tex} = 1,000 \times 1\frac{1}{2} = 1,500km{/tex}
Similarly, distance traveled by the plane flying towards west in {tex}1\frac{1}{2}{/tex}hrs
{tex} = 1,200 \times 1\frac{1}{2} = 1,800km{/tex}
Let these distances are represented by OA and OB respectively.
Now applying Pythagoras theorem
Distance between these planes after {tex}1\frac{1}{2}{/tex}hrs {tex}AB = \sqrt {O{A^2} + O{B^2}} {/tex}
{tex} = \sqrt {{{(1,500)}^2} + {{(1,800)}^2}}{/tex} {tex}= \sqrt {2250000 + 3240000}{/tex}
{tex} = \sqrt {5490000} = \sqrt {9 \times 610000} = 300\sqrt {61} {/tex}
So, distance between these planes will be {tex}300\sqrt {61} {/tex}km, after {tex}1\frac{1}{2}{/tex}hrs.
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