Find the roots of the equation …

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Sia ? 6 years, 6 months ago
5x2 - 6x - 2 = 0
Multiplying the above equation by 1/5
{tex} \Rightarrow {x^2} - \frac{6}{5}x - \frac{2}{5} = 0{/tex}
{tex}\Rightarrow x ^ { 2 } - \frac { 6 } { 5 } x + \left( \frac { 3 } { 5 } \right) ^ { 2 } - \left( \frac { 3 } { 5 } \right) ^ { 2 } - \frac { 2 } { 5 } = 0{/tex}
{tex}\Rightarrow \left( x - \frac { 3 } { 5 } \right) ^ { 2 } = \frac { 9 } { 25 } + \frac { 2 } { 5 }{/tex}
{tex}\Rightarrow \left( x - \frac { 3 } { 5 } \right) ^ { 2 } = \frac { 9 + 10 } { 25 }{/tex}
{tex}\Rightarrow \left( x - \frac { 3 } { 5 } \right) ^ { 2 } = \frac { 19 } { 25 }{/tex}
{tex}\Rightarrow x - \frac { 3 } { 5 } = \pm \frac { \sqrt { 19 } } { 5 }{/tex}
{tex}\Rightarrow x = \frac { 3 } { 5 } \pm \frac { \sqrt { 19 } } { 5 }{/tex}
{tex}\Rightarrow x = \frac { 3 + \sqrt { 19 } } { 5 } \text { or } x = \frac { 3 - \sqrt { 19 } } { 5 }{/tex}
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