If A(-2,1) B(a,0) C(4,b) D(1,2) are …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Test
Related Questions
Posted by Lakshay Kumar 1 year, 1 month ago
- 0 answers
Posted by Hari Anand 6 months, 1 week ago
- 0 answers
Posted by Parinith Gowda Ms 3 months, 2 weeks ago
- 1 answers
Posted by Vanshika Bhatnagar 1 year, 4 months ago
- 2 answers
Posted by Parinith Gowda Ms 3 months, 2 weeks ago
- 0 answers
Posted by Kanika . 1 month ago
- 1 answers
Posted by Sahil Sahil 1 year, 4 months ago
- 2 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Sia ? 6 years, 6 months ago
Given, A (-2,-1), B (a, 0), C (4, b) and D (1, 2)
We know that the diagonals of a parallelogram bisect each other.
Therefore, the coordinates of the mid-point of AC are same as the coordinates of the mid-point of BD i.e.
{tex}\left( \frac { - 2 + 4 } { 2 } , \frac { - 1 + b } { 2 } \right) = \left( \frac { a + 1 } { 2 } , \frac { 0 + 2 } { 2 } \right){/tex}
{tex}\Rightarrow \quad \left( 1 , \frac { b - 1 } { 2 } \right) = \left( \frac { a + 1 } { 2 } , 1 \right){/tex}
{tex}\Rightarrow \frac { a + 1 } { 2 } = 1 \text { and } \frac { b - 1 } { 2 } = 1{/tex}
{tex}\Rightarrow{/tex}{tex}a + 1 = 2 \ and \ b - 1 = 2{/tex}
{tex}\Rightarrow{/tex}{tex}a = 1 \ and \ b = 3{/tex}
Hence, {tex}a = 1 \ and \ b = 3{/tex}
0Thank You