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Find the area of the minor segment of a circle of radius 42cm, if length of the corresponding arc is 44cm

Posted by Sudhanshu Singh 7 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 7 years, 3 months ago

{tex}\;\frac\theta{360\;}\times{/tex}2 πr = 44
Putting r = 42cm, we get= 60°
Now, Area of minor segmen t= Area of minor sector-Area of ∆
Since = 60°, so the triangle formed will be an equilateral ∆
Area of minor segment = Area of minor sector-Area of equilateral ∆
i.e. Area of minor segment = {tex}\;\frac\theta{360\;}\times\mathrm{πr}^2\;-\;\frac{\sqrt3}4\mathrm a^{{}^2}{/tex}

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