2sin€- 3

CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Gaurav Bajaj 6 years, 6 months ago
- 1 answers
Related Questions
Posted by Vanshika Bhatnagar 1 year, 4 months ago
- 2 answers
Posted by Parinith Gowda Ms 3 months, 2 weeks ago
- 1 answers
Posted by Parinith Gowda Ms 3 months, 2 weeks ago
- 0 answers
Posted by Sahil Sahil 1 year, 4 months ago
- 2 answers
Posted by Kanika . 1 month ago
- 1 answers
Posted by Lakshay Kumar 1 year, 1 month ago
- 0 answers
Posted by Hari Anand 6 months, 1 week ago
- 0 answers

myCBSEguide
Trusted by 1 Crore+ Students

Test Generator
Create papers online. It's FREE.

CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
myCBSEguide
Sia ? 6 years, 6 months ago
We know that, Sin30° =(1/2), Cos45°=(1/√2), tan60°=√3, putting these values in the given expression, we get :-
{tex}2{\sin ^2}30^\circ - 3{\cos ^2}45^\circ + {\tan ^2}60^\circ {/tex}
{tex} = 2{\left( {\frac{1}{2}} \right)^2} - 3\left( {\frac{1}{{\sqrt 2 }}} \right)^2+ {\left( {\sqrt 3 } \right)^2}{/tex}
{tex} = \frac{2}{4} - \frac{3}{2} + 3{/tex}
{tex} = \frac{{2 - 6 + 12}}{4}{/tex}
{tex} = \frac{8}{4} = 2{/tex}
0Thank You