5^(x+1)+5^(2-x)=5^3+1

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Sia ? 6 years, 6 months ago
Given,
5(x+1) + 5(2 - x) = 53 +1
{tex}\Rightarrow{/tex} 5x.5 + 52.5-x = 125 + 1
{tex}\Rightarrow{/tex} 5x.5 + {tex}\frac { 25 } { 5 ^ { x } }{/tex} = 126
Let {tex}y =5^x{/tex}
{tex}\Rightarrow{/tex} 5y + {tex}\frac { 25 } { y }{/tex} = 126
{tex}\Rightarrow5y^2+25=126y{/tex}
{tex}\Rightarrow{/tex} 5y2 - 126y + 25 = 0
Factorise the equation,
{tex}\Rightarrow{/tex} 5y2 - 125y - y + 25 = 0
{tex}\Rightarrow{/tex} 5y(y - 25) -1 (y - 25) = 0
{tex}\Rightarrow{/tex}(y - 25) (5y - 1) = 0
{tex}\Rightarrow{/tex} y - 25 = 0 or 5y - 1 = 0
{tex}\Rightarrow{/tex} y = 25 or y = 1/5
Now,
{tex}\Rightarrow{/tex} 5x = 25 or 5x = 1/5
{tex}\Rightarrow{/tex} 5x = 52 or 5x = 5-1
{tex}\Rightarrow{/tex} x = 2 or x = -1.
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