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Find the value of k for …

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Find the value of k for which the points (3k-1,k-2), (k,k-7) , and (k-1,-k-2) are collinear.
  • 6 answers

S Sihag Ji 6 years, 11 months ago

Thanks bhai

Shivam The Galaxy 6 years, 11 months ago

Equation will be like this 4k^2 -12k+0=0 then taking 4k as common then 4k(k-3)=0 And u will get the answer as mentioned

Shivam The Galaxy 6 years, 11 months ago

Right answer is K=0 and K = 3

S Sihag Ji 6 years, 11 months ago

2k^2-6k-5=0,meri ye equation ban rhi hai , but k ki value nhi aa rhi

You . 6 years, 11 months ago

Answer KYa aa rha h mera to koi square = 3k aa rha h

S Sihag Ji 6 years, 11 months ago

Plz solve this problem
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