Find the value of x for …

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Sia ? 6 years, 6 months ago
Since {tex}(5x+2), (4x-1)\ and\ (x+2){/tex} are in AP, we have
{tex}(4x-1)-(5x+2)=(x+2)-(4x-1){/tex}
{tex}\Rightarrow{/tex} {tex}4x-1-5x-2=x+2-4x+1{/tex}
{tex}\Rightarrow{/tex} {tex}-x-3=-3x+3{/tex}
{tex}\Rightarrow{/tex} 2x = 6
{tex}\Rightarrow{/tex} x = 3.
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