Two vertices of triangle are (1,2) …

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Sia ? 6 years, 6 months ago
Let the coordinates of the third vertex be (x, y), Then
Coordinates of centroid of triangle are
{tex}\left( {\frac{{x + 1 + 3}}{3},\frac{{y + 2 + 5}}{3}} \right){/tex}
We have centroid is at origin (0, 0)
{tex}\therefore \frac{{x + 1 + 3}}{3} = 0{/tex} and {tex}\frac{{y + 2 + 5}}{3} = 0{/tex}
{tex}\Rightarrow{/tex} x + 4 = 0 {tex}\Rightarrow{/tex} y + 7 = 0
{tex}\Rightarrow{/tex} x = -4 {tex}\Rightarrow{/tex} y = -7
Hence, the coordinates of the third vertex are (-4, -7).
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