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If secA=x+1/4x, Prove that secA+tanA=2x or …

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If secA=x+1/4x, Prove that secA+tanA=2x or 1/2x
  • 7 answers

S Sihag Ji 6 years, 11 months ago

Thanks

Saumya Saini 6 years, 11 months ago

SecA=x+1/4x ∴, sec²A=(x+1/4x)² =x²+2.x.1/4x+1/16x² =x²+1/2+1/16x² Now, sec²A-tan²A=1 or, tan²A=sec²A-1 ∴, either, secA+tanA =x+1/4x+x-1/4x [when tanA=x+1/4x] =2x   ______________ or, secA+tanA =x+1/4x-x+1/4x [when tanA=-(x+1/4x)] =1/4x+1/4x =2/4x =1/2x

@Kumu...#Vk... ?? 6 years, 11 months ago

Kl hi h shivangi

S Sihag Ji 6 years, 11 months ago

Aacha ek baat btao physics ka test kal hai ya parso

S Sihag Ji 6 years, 11 months ago

Okk,???

Sushma Bhattoo 6 years, 11 months ago

I will tell you the solution in class.

S Sihag Ji 6 years, 11 months ago

Sushma didi please solve my problem
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