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find the sum of the first 50 odd natural numbers by using arithmetic progression

Posted by Archana Sarode 6 years, 11 months ago

CBSE > Class 10 > Mathematics

3 answers

Ravi Jindal 6 years, 11 months ago

1,3,5 is correct in place 1,2,3

1Thank You

Ravi Jindal 6 years, 11 months ago

1,2,3....... a=1,d=2,n=50 S=n/2(2a+(n-1)d) S=50/2(2(1)+(50-1)2 S=25(2+(49)2) S=25(2+98) S=25(100) S=2500

1Thank You

Yogita Ingle 6 years, 11 months ago

The first 50 natural odd numbers = 1,3,5,7... (upto 50 terms) which is an AP.
Now, s_n = n/2 [2a + (n-1)d]
S₅₀ = 50/2 [2x1 + (50-1)2]
= 25 (2 + 98)
= 25 x 100
= 2500

1Thank You

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