(Sin^3A+cos^3A/sinA+cosA) + sinAcosA
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Ram Kushwah 7 years ago
{tex}\begin{array}{l}\frac{\sin\;^3A\;+\cos^3A}{\sin A+\cos A}+\;\sin AcosA\\={\textstyle\frac{\textstyle(\sin A\;+\;\cos A)(\sin^2A+\cos^2A-\sin A\cos A)}{\sin{\textstyle A}{\textstyle\;}{\textstyle+}{\textstyle\cos}{\textstyle A}}}\;+\;\sin AcosA\\=\sin^2A+\cos^2A-\sin A\cos A+\;\sin AcosA\\=1\\\end{array}{/tex}
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