Estrification and saponification reaction

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Estrification and saponification reaction

Posted by Ankit Raj 7 years ago

CBSE > Class 10 > Science

2 answers

Chētnà Pandey✌️ 7 years ago

When a carboxylic acid is treated with an alcohol and an acid catalyst, an ester is formed (along with water). This reaction is called the Fischer esterification.✔️ Saponification:Esters react in the presence of an acid or a base to give back the alcohol and carboxylic acid. This is called saponification reaction. This is reverse reaction of esterification reaction. CH3COOC2H5 + NaOH → CH3-COOH + CH3-CH2-OH

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Yogita Ingle 7 years ago

Esterification: The reaction between Acid and an Alcohol to produce ester as the product is called Esterification reaction. During this reaction a molecule of water is eliminated.

Ex: CH₃COOH + C₂H₅OH →CH₃COOC₂H₅ + H₂O

In the above reaction Ethanoic acid reacted Ethyl alcohol to form an ester Ethyl Acetate and water molecule.

Saponification: Esters react in the presence of an acid or a base to give back the alcohol and carboxylic acid. This is called saponification reaction. This is reverse reaction of esterification reaction.

CH₃COOC₂H₅ + NaOH → CH₃-COOH + CH₃-CH₂-OH

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