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3cota=4. Find 5sinA+3cosA÷5sinA-3cosA

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3cota=4. Find 5sinA+3cosA÷5sinA-3cosA
  • 2 answers
Here 3cotaa=4 Cota=b/p=4/3(4=b,3=p) Now you find h=5 SinA=p/h 5sina=5•3/5 =3 3cosa=4/5= =12/5 Now, 5sina+3cosa ➗ 5sina-3cosa(put the value that we find) 3+12/5 ➗ 3-12/5 27/5 ➗ 3/5 =9 answer

Happy Kumar 7 years ago

Ans 9
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