The short and long hands of …

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Sia ? 6 years, 6 months ago
According to the question,we have to find the sum of the distances travelled by the short and long hands of clock in 2 days.
Short hand completes 1 round in 12 hours
{tex}\therefore{/tex}Distance covered by tip of short hand in 12 hours = circumference of circle = {tex}2 \times \frac { 22 } { 7 } \times 4 = \frac { 176 } { 7 }{/tex} cm
Distance covered in 2 days (48 hours) = 4 {tex}\times \frac { 176 } { 7 }{/tex} cm
Long hand completes 1 round in 1 hour
Distance covered by the tip of long hand in 1 hour = 2{tex}\times \frac { 22 } { 7 } \times 6 = \frac { 264 } { 7 }{/tex}cm
Distance covered in 2 days = 48{tex}\times \frac { 264 } { 7 }{/tex} cm
Total distance covered = {tex}\frac { 4 \times 176 } { 7 } + \frac { 48 \times 264 } { 7 }{/tex}= 1910.86 cm
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