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A toy is in the form

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A toy is in the form

Posted by Gulshan Kumar 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Radius of the cone = 3.5 cm
{tex}\therefore {/tex} Radius of the hemisphere = 3.5 cm
Total height of the toy = 15.5 cm
{tex}\therefore {/tex} Height of the cone = 15.5 - 3.5 = 12 cm
Slant height of the cone = {tex}\sqrt {{{(3.5)}^2} + {{(12)}^2}} = \sqrt {12.25 + 144} {/tex}
{tex} = \sqrt {156.25} {/tex} = 12.5 cm
{tex}\therefore {/tex} Total surface area of the toy = Curved surface area of hemisphere + Curved surface area of cone
{tex} = 2\pi {r^2} + \pi rl = 2\pi {(3.5)^2} + \pi (3.5)(12.5){/tex}
{tex} = 24.5\pi + 43.75\pi = 68.25\pi = 68.25 \times \frac{{22}}{7}{/tex} = 214.5 cm²

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CBSE > Class 10 > Mathematics