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Find HCF of 65 and 117 …

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Find HCF of 65 and 117 and express it in the form 65m + 117n

    • Posted by Praveena Ananth 7 years ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Akash Chaudhary 7 years ago

    HCF = 13 13 = 65m + 117n From [ 1] , 13 = 65 - 52 x 1 From [2] , 52 = 117 - 65 x 1 ----> [3] Hence , 13 = 65 - [ 117 - 65 x 1 ] ------> from [3] = 65 x 2 - 117 = 65 x 2 + 117 x [-1 ] m = 2 n = -1

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    Akash Chaudhary 7 years ago

    HCF = 13 13 = 65m + 117n From [ 1] , 13 = 65 - 52 x 1 From [2] , 52 = 117 - 65 x 1 ----> [3] Hence , 13 = 65 - [ 117 - 65 x 1 ] ------> from [3] = 65 x 2 - 117 = 65 x 2 + 117 x [-1 ] m = 2 n = -1 Read more on Brainly.in - https://brainly.in/question/1192640#readmore

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