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Find the sum of three-digit multipleis …

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Find the sum of three-digit multipleis natural number , which is divisible by 11

Posted by Mahak Mishra 7 years ago

CBSE > Class 10 > Mathematics

3 answers

Ram Kushwah 7 years ago

Sorry there was some mistaken

990=110+(n-1)*11

880=11n-11

11n=891 so n=81

Sn= 81/2( 2*110+80*11)=81/2 * 1100=44550

0Thank You

Abhishek Gupta 7 years ago

110,121,..........990 Than A=110 D=121-110=11 An=990 An =a+(n-1)d 990=110+(n-1)11 990=110+11n-11 990=99+11n Or 11n=990-99 n=891/11=81

0Thank You

Ram Kushwah 7 years ago

Here first term a= 110, d=11 and last term =990

suppose no. of terms =n

then 990= 110 +(n-1) x 11 (n^th term of AP)

n-1=8 so n=9

sum of all the numbers

= 9/2x( 2x110 + 8x11)

=9/2 x ( 220+88) = 1386

0Thank You

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