27rest to x=9upon 3rest to x …

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Amar Kumar 8 years, 6 months ago
{tex}\eqalign{ & {{{{27}^x}} \over {{3^x}}} = 9 \cr & {\left( {{{27} \over 3}} \right)^x} = 9 \cr & {9^x} = {9^1} \cr & x = 1 \cr & \cr} {/tex}
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