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tan A + sec A -1÷tan …

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tan A + sec A -1÷tan A-secA+1=1+sinA÷cosA

Posted by Muskan Chhilar 7 years ago

CBSE > Class 10 > Mathematics

3 answers

Ram Kushwah 7 years ago

Proof:

LHS=(tanA +secA) - (sec²A - tan²A) / tanA + 1 - secA as sec²A - tan²A=1

=(tanA+ secA) (1 - (secA - tanA))/tanA + 1 - secA

=(tanA +secA) (1 - secA + tanA) / (1 - secA+tanA )

=sec A + tan A

=1/cosA + sinA/cosA

=(1 + sinA) / cosA =RHS

0Thank You

Kalai Amudhan 7 years ago

It is in this app itself. It is in the exercise 8.3 of exemplar problems of chapter intro to trigonometry

1Thank You

Muskan Chhilar 7 years ago

Prove this

1Thank You

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Posted by Kanika . 1 month ago

CBSE > Class 10 > Mathematics