If HCF of 408 & 1032 …

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Yogita Ingle 7 years ago
If the HCF of 408 and 1032 can be written as
By Euclid 's division algorithm,
1032 = 408×2 + 216
408 = 216×1 + 192
216 = 192×1 + 24
192 = 24×8 + 0
Since the remainder becomes 0 here, so HCF of 408 and 1032 is 24
Now,
1032x - 408*5 = HCF of these numbers
⇒ 1032x - 2040 = 24
⇒ 1032x = 24+2040
⇒ x = 2064/1032
⇒ x = 2
So value of x is 2.
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