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SinA+cosA=√2cosA ,prove that cosA-sinA=√2sinA

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SinA+cosA=√2cosA ,prove that cosA-sinA=√2sinA
  • 1 answers

Purvanshi Yadav 7 years, 1 month ago

SinA+cosA=√2cosA SinA=√2cosA-cosA SinA=(√2-1)cosA SinA=(√2-1÷1×√2+1÷√2+1)×cosA SinA=(2-1÷√2+1)×cosA SinA=cosA÷√2+1 (√2-1)×sinA=cosA √2sinA+sinA=cosA √2sinA=cosA-sinA
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