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If A and G be A.M. …

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If A and G be A.M. and G.M., respectively between two positive numbers, prove that the numbers are A+_under root(A+G)(A--G).

    • Posted by Shivshant Upadhyay 7 years, 2 months ago

    CBSE > Class 11 > Mathematics
    • 2 answers

    Hemant Rathod 7 years, 2 months ago

    A.M=a+b/2 =A .G.M =√ab =G. Put A and G in. Given eqn. (a+b/2-√ab) ^2

    0Thank You

    Shreesha Bharadwaj 7 years, 2 months ago

    2A=a+b g^2=ab x^2--(a+b)+ab x^2-2A+g^2 x=-b+_ squareroot of (b^2-4ac)/2a 2A+_square root of (4A^2_--4*1*G^2) /2*1 2A+_squareroot of 4 * (A^2-G^2) /2 2A+2 square root of (A+G)(A-G) ÷2 2(A+square root of (A+G)(A-G) ÷2 A+_squareroot of (A+G)(A-G) proved

    2Thank You

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