If ABC is a equilateral triangle …

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Sia ? 6 years, 6 months ago
According to the question, {tex}\triangle ABC {/tex} is an equilateral triangle.

In {tex}\triangle{/tex}ABD, using Pythagoras theorem,
{tex}\Rightarrow{/tex} AB2 = AD2 + BD2
{tex}\Rightarrow{/tex} BC2 = AD2 + BD2, (as AB = BC = CA)
{tex}\Rightarrow{/tex} (2 BD)2 = AD2 + BD2, (perpendicular is the median in an equilateral triangle)
{tex}\Rightarrow{/tex} 4BD2 - BD2 = AD2
{tex}\therefore{/tex} 3BD2 = AD2
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