A fez the cap used by …
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Sia ? 6 years, 6 months ago
Clearly, the fez is in the shape of a frustum of a cone with radii of one base as {tex}r_1{/tex} = 10 cm and radii of another base as {tex}r_2{/tex} = 4 cm and slant height l = 15 cm. Let A be the area of the material used. Then,
A = Curved surface area + Area of the closed base
{tex}\Rightarrow \quad A = \pi \left( r _ { 1 } + r _ { 2 } \right) l + \pi r _ { 2 } ^ { 2 }{/tex}
{tex}\Rightarrow \quad A = \left\{ \frac { 22 } { 7 } \times ( 10 + 4 ) \times 15 + \frac { 22 } { 7 } \times 4 ^ { 2 } \right\} \mathrm { cm } ^ { 2 }{/tex}
{tex}\Rightarrow \quad A = \left( 352 \times 2 \times 15 + \frac { 352 } { 7 } \right) \mathrm { cm } ^ { 2 } = \left( 660 + \frac { 352 } { 7 } \right) \mathrm { cm } ^ { 2 } = 660 + 50.28 \mathrm { cm } ^ { 2 }{/tex}= 710.28cm2.
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