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Sec²theta + cosec²theta = sec²theta cosec …

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Sec²theta + cosec²theta = sec²theta cosec ²theta

Posted by Satish Kumar 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

We have,
LHS = cosec²{tex}\theta{/tex} + sec²{tex}\theta{/tex}
{tex}\Rightarrow \quad \mathrm { LHS } = \frac { 1 } { \sin ^ { 2 } \theta } + \frac { 1 } { \cos ^ { 2 } \theta }{/tex}
{tex}\Rightarrow \quad \mathrm { LHS } = \frac { \cos ^ { 2 } \theta + \sin ^ { 2 } \theta } { \cos ^ { 2 } \theta \sin ^ { 2 } \theta } = \frac { 1 } { \sin ^ { 2 } \theta \cos ^ { 2 } \theta } = \frac { 1 } { \sin ^ { 2 } \theta } \times \frac { 1 } { \cos ^ { 2 } \theta } = \operatorname { cosec } ^ { 2 } \theta \sec ^ { 2 } \theta{/tex} = RHS

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CBSE > Class 10 > Mathematics