5m wide cloth to make a …

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Sia ? 6 years, 6 months ago
Given: Radius of base (r) and height (h) of the conical tank are 7 m and 24 m
⇒ Slant height (l) = r2 + h2
{tex}= \sqrt { r ^ { 2 } + h ^ { 2 } } = \sqrt { 7 ^ { 2 } + 24 ^ { 2 } }{/tex}
{tex}= \sqrt { 625 } = 25 \mathrm { m }{/tex}
C.S.A. {tex}= \pi r l{/tex}
{tex}= \frac { 22 } { 7 } \times 7 \times 25 = 550 \mathrm { m } ^ { 2 }{/tex}
Let x m of cloth is required
CSA of tent = area of cloth.
or, {tex}5 x = 550 \text { or, } x = \frac { 550 } { 5 } = 110 \mathrm { m }{/tex}
{tex}\therefore{/tex} 110 m of cloth is required.
Cost of cloth {tex}= 25 \times 110 = Rs. 2750{/tex}
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