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Sin(x+y)/sin(x-y)=tanx+tany/tanx-tany prove that

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Sin(x+y)/sin(x-y)=tanx+tany/tanx-tany prove that
  • 1 answers

Vivek G 7 years, 2 months ago

sin(x+y)=sinx.cosy+cosx.siny. sin(x-y)=sinx.cosy-cosx.siny. sin(x+y)/sin(x-y)={sinx.cosy+cosx.siny}/{sinx.cosy-cosx.siny}. divide each term by cosx.cosy. :it becomes tanx+tany/tanx-tany
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