Find hcf of the number given …

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Sia ? 6 years, 4 months ago
{tex}\begin{array}{l}k=\;k\times1\\2k=\;k\times2\\3k=k\times3\\4k=k\times2\times2\\5k=k\times5\end{array}{/tex}
Here k is a positive integer
Hence HCF(k,2k,3k,4k,5k)= k.
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