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Two primary cells of emf's E1 …

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Two primary cells of emf's E1 and E2 are connected to the potentiometer wire AB.If the balancing length for the two combinations of the cells are 250 cm and 400 cm .Find the ratio of E1 and E2

Posted by Nishant Sharma 7 years, 1 month ago

CBSE > Class 12 > Physics

1 answers

Chinmay Pal Singh 7 years, 1 month ago

As we know that, E = kl where, l is the length of potentiometer wire, and, k is potential gradient, Acc. to question, E1 = kl1 =>. E1 = k250; E2 = kl2. =>. E2 = k400; =>. E1/E2 = kl1/kl2 =>. E1/E2 = k250/k400; =>. E1/E2 = 250/400. ---answer

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