Two vertices of a triangle are …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Sharlin Thomas 6 years, 6 months ago
- 1 answers
Test
Related Questions
Posted by Hari Anand 6 months ago
- 0 answers
Posted by Kanika . 4 weeks, 1 day ago
- 1 answers
Posted by Sahil Sahil 1 year, 4 months ago
- 2 answers
Posted by Vanshika Bhatnagar 1 year, 4 months ago
- 2 answers
Posted by Parinith Gowda Ms 3 months, 1 week ago
- 0 answers
Posted by Parinith Gowda Ms 3 months, 1 week ago
- 1 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Sia ? 6 years, 6 months ago
Let the coordinates of the third vertex be (x, y). Then by centroid formula, coordinates of centroid of given triangle are,
{tex}\left( \frac { x - 3 + 0 } { 3 } , \frac { y + 1 - 2 } { 3 } \right) = \left( \frac { x - 3 } { 2 } , \frac { y - 1 } { 3 } \right){/tex}
We have centorid is at origin (0, 0)
{tex}\therefore \frac { x - 3 } { 3 } = 0 \quad \text { and } \frac { y - 1 } { 3 } = 0{/tex}
{tex}\Rightarrow{/tex}x - 3 = 0 {tex}\Rightarrow{/tex}y - 1 = 0
{tex}\Rightarrow{/tex}x = 3{tex}\Rightarrow{/tex}y = 1
Hence, the coordinates of the third vertex are (3, 1).
0Thank You