The time taken by a person …

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Sia ? 6 years, 6 months ago
Let the speed while going be x km/h
{tex}\therefore {/tex}Speed while returning = (x + 10) km/h
According to question
{tex}\frac { 150 } { x } - \frac { 150 } { x + 10 } = \frac { 5 } { 2 }{/tex}
or, {tex}x ^ { 2 } + 10 x - 600 = 0{/tex}
or, (x -f 30) (x - 20) = 0
or, x=20
{tex}\therefore {/tex} Speed while going =20 km/h
and speed while returning = 20 + 10 = 30 km/h
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