The LCM of two no.is 14 …

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Sia ? 6 years, 6 months ago
Let a and b are numbers and HCF = x
Then LCM = 14x
Now sum of HCF and LCM
x+14x =600
15x = 600
x = 40
Hence HCF=40 and LCM=14{tex}\times{/tex}40
Given a=280 and b=?
We know that
a {tex}\times{/tex} b = HCF {tex}\times{/tex} LCM
So {tex}\mathrm b=\frac{40\times14\times40}{280}=2\times40=80{/tex}
Hence the other number = 80
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