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Ncert exercise q no 2.4

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Ncert exercise q no 2.4

Posted by Viru Yadav 7 years, 2 months ago

CBSE > Class 12 > Chemistry

1 answers

Dhruv G 7 years, 2 months ago

Let total mass=100g. 68% Nitric acid(HNO3) in aqueous solution=> 68g hno3 in 100-68g water. Use formula=> molarity=(moles of solute)*1000/(vol. of solution)➡find out moles➡in formula volume ko equal kro = mass(=100g)/density(given=1.504g/ml)➡ans-16.23mol/L?

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