Rationalize 1/√7-√3

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Ilu Ahirwar 8 years, 6 months ago
Sol. {tex}1\over \sqrt{7}-\sqrt{3}{/tex}* {tex}\sqrt{7}+\sqrt{3}\over \sqrt{7}+\sqrt{3}{/tex}
{tex}\sqrt{7}+\sqrt{3} \over (\sqrt{7})^2- (\sqrt{3})^2{/tex} ....({tex}(a^2-b^2)=(a-b)(a+b){/tex})
{tex}\sqrt{7}+\sqrt{3} \over 7-3{/tex}
{tex}\sqrt{7}+\sqrt{3} \over 4{/tex}.
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