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Find the ratio in which the line segment joining the point -3and 10 and 6and -8 is divided by -1 and 6

Posted by Pankaj Naik 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

Let (-1, 6) divides line segment joining the points (-3, 10) and(6, -8) in k:1.
Using Section formula, we get
{tex} - 1 = \frac{{( - 3) \times 1 + 6 \times k}}{{k + 1}}{/tex} {tex}4 \Rightarrow - k - 1 = ( - 3 + 6k){/tex}
⇒ −7k = −2 ⇒ k= {tex}\frac{2}{7}{/tex}
Therefore, the ratio is {tex}\frac{2}{7}:1{/tex} which is equivalent to 2:7.
Therefore, (-1, 6) divides line segment joining the points (-3, 10) and (6, -8) in 2:7.

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CBSE > Class 10 > Mathematics