Metallic spheres of radii 6cm 8cm …

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Sia ? 6 years, 6 months ago
Sum of the volumes of three given spheres = {tex}\frac43\mathrm\pi{/tex}[(6)3 + (8)3 + (10)3]
= {tex}\frac43\mathrm\pi{/tex}[216 + 512 + 1000]
= {tex}\frac43\mathrm\pi{/tex} × 1728 = 4{tex}\pi{/tex} × 576 = 2304π cm3
Let R be the radius of single solid sphere, since volume remains the same
∴ {tex}\frac43\mathrm\pi{/tex}R3 = 2304 {tex}\pi{/tex}
⇒ R3 ={tex}\frac{2304\times3}4=\;576\times3{/tex}
⇒ R3 = 1728 = (12)3
∴ R = 12 cm
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